AP ICET 11 Sep 2020 Shift 1 Paper

Question : 121 of 200

Marks: +1, -0

Algebraic and Geometrical Ability

From the top of a vertical cliff of 40m high, the angle of depression of an object that is at the base level of the cliff is 30°. If the object is at a distance x units from the base of the cliff, then

1/x+40=

${√3-1}/80$
${4√3}/40$
$1/{40√3}$
$1/{40-√3}$

Validate

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