AP ICET 10 Sep 2020 Shift 1 Paper

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Question : 129 of 200

Marks: +1, -0

In a geometric progression with positive common ratio, the ratio of

13^{\;\text "th "\;}

term to the

7^{\;\text "th "\;}

term is

27: 1

then the ratio of its

9^{\;\text "th "\;}

term to

16^{\;\text "th "\;}

term is

$\;{1}/{3 √{3}}$
$\;{1}/{9}$
$\;{1}/{9 √{3}}$
$\;{1}/{27 √{3}}$

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