An electron of mass ' m ' with initial velocity \overrightarrow{v}=v_0 \stackrel{\^}{𝑖} (v_0>0) enters in an electric field \overrightarrow{E}=-E_0 \stackrel{\^}{𝑖} [E_0. is constant >0] gt;0] at t=0. If \lambda is its de-Brogli wavelength initially, then the de-Brogli wave length after time ' t ' is [AP EAPCET 20 May 2024 Shift 1]

Correct Answer is : λ1+eE0tmv0

{\lambda}/{1+\frac{ {\e} E_0 t}{m v_0}}

{\lambda}/{ (1-\frac{e E_0 t}{m v_0}) ^2}

(1+\frac{e E_0 t}{m v_0}) \lambda

(1+\frac{e E_o t}{m v_o}) ^2 \lambda

Dual Nature of Matter and Radiation

Section: Physics

Question : 14 of 16

Marks: +1, -0

An electron of mass ' m ' with initial velocity

→

=v0

𝑖

(v0>0) enters in an electric field

→

=−E0

𝑖

[E0. is constant >0] at t=0. If λ is its de-Brogli wavelength initially, then the de-Brogli wave length after time ' t ' is

[AP EAPCET 20 May 2024 Shift 1]

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