Heat and Thermodynamics

Let m= mass of steam condensed. Then, m grams of steam forms m grams of water at 100∘C which further losses heat and comes at 90∘C.
Final mixture is water at 90∘C
Now using Heat lost = Heat gained, we gel
Heat lost by steam in condensation + Heat lost by water formed at 100∘C
= Heat gained by water at 24∘C
‌⇒mL+mc(100−90)=100(c)(90−24)
‌⇒m(540+1×10)=100×1×66
‌⇒m=‌

100×66

550

=‌

10×6

5

=12g