Steam at 100^{\circ} {\C} is passed into 114 g of water at 30^{\circ} {\C}. The mass of water present in the mixture when the temperature of the water becomes 70^{\circ} {\C} is (Latent heat of steam =540 {\cal} {\g}^{-1}; specific heat capacity of water =1 {\cal} {\g}^{-1}{ }^{\circ} {\C}^{-1} ) [AP EAPCET 23 May 2025 S1]

Heat and Thermodynamics

Section: Physics

Question : 16 of 78

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Steam at 100∘C is passed into 114 g of water at 30∘C. The mass of water present in the mixture when the temperature of the water becomes 70∘C is (Latent heat of steam =540‌cal‌g−1; specific heat capacity of water =1‌cal‌g−1‌‌∘‌C−1 )

[AP EAPCET 23 May 2025 S1]

122g
132g
142g
152g

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