Fluid Mechanics

Mass of the aeroplane, m=4.5×104kg
Total wing area, A=600m2
Acceleration due to gravity, g=10m∕s2
The aeroplane is travelling at a constant height, meaning lift = weight.
Step 1. Lift = Pressure difference × Area
L=∆P×A
Step 2. Lift = Weight
L=mg
So,
∆P×A=mg
Step 3. Solve for pressure difference
∆P=‌

mg

A

Substitute the known values:
‌∆P=‌

4.5×104×10

600

‌∆P=‌

4.5×105

600

‌∆P=750N∕m2
Answer: 750N∕m2