The elongation of copper wire of cross-sectional area 3.5 {\mm}^2, in the figure shown, is (\Y_{\text{Copper }}=10 \times 10^{10} {\Nm}^{-2}. and {\g}=10 {\ms}^{-2}) [AP EAPCET 22 May 2024 Shift 1]

Elasticity

Section: Physics

Question : 12 of 17

Marks: +1, -0

The elongation of copper wire of cross-sectional area 3.5mm2, in the figure shown, is (Y‌Copper ‌=10×1010Nm−2. and g=10ms−2)

[AP EAPCET 22 May 2024 Shift 1]

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