The equation for { }_{10} {\Ne}^{23} nucleus which decays by \beta-emission is

Correct Answer is : 10Ne23β-decay ───────▶11Na23+e−+V

{ }_{10} {\Ne}^{23} \stackrel{{\beta \text{-decay }\xrightarrow}}_{10} {\Ne}^{23}+\overline{ {\V}}+ {\e}^{-}

_10\Ne^{23} \stackrel{{\beta \text{-decay }\xrightarrow}}{ }_{10} {\Ne}^{23}+v+ {\e}^{-}

{ }_{10} {\Ne}^{23} \stackrel{{\beta \text{-decay }\xrightarrow}}{ }_{11} {\Na}^{22}+ {\e}^{-}+\overline{ {\V}}

{ }_{10} {\Ne}^{23} \stackrel{{\beta \text{-decay }\xrightarrow}}{ }_{11} {\Na}^{23}+ {\e}^{-}+\overline{ {\V}}

AP EAPCET Medical 19 May 2025 Shift 1 Paper

Question : 117 of 160

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The equation for ‌10Ne23 nucleus which decays by β-emission is

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