For a positive real number p, if the perpendicular distance from a point -\overline{ {\i}}+ {\p} \overline{ {\j}}-3 \overline{ {\k}} to the plane \overline{ {\r}} \cdot(2 \overline{ {\i}}-3 \overline{ {\j}}+6 \overline{ {\k}})=7 is 6 units, then {\p}= [AP EAPCET 22 May 2025 S2]

Three Dimensional Geometry

Section: Mathematics

Question : 13 of 58

Marks: +1, -0

For a positive real number p, if the perpendicular distance from a point −i+pj−3k to the plane r⋅(2i−3j+6k)=7 is 6 units, then p=

[AP EAPCET 22 May 2025 S2]

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