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Question : 90 of 92
Marks:
+1 ,
-0
Solution:
To find the probability that the target is hit by
P or
Q but not by
R , let's define the events:
E 1 : P hits the target.
E 2 : Q hits the target.
E 3 : R hits the target.
The given probabilities are:
‌ P ( E 1 ) = ‌ ‌ P ( E 2 ) = ‌ ‌ P ( E 3 ) = ‌ These events are independent, so:
The probability that
P hits and both
Q and
R miss is:
P ( E 1 ∩ E 2 ∩ E 3 ) = P ( E 1 ) ⋅ ( 1 − P ( E 2 ) ) ⋅ ( 1 − P ( E 3 ) ) = ‌ ⋅ ‌ ⋅ ‌ The probability that
Q hits and both
P and
R miss is:
P ( E 1 ∩ E 2 ∩ E 3 ) = ( 1 − P ( E 1 ) ) ⋅ P ( E 2 ) ⋅ ( 1 − P ( E 3 ) ) = ‌ ⋅ ‌ ⋅ ‌ The probability that both
P and
Q hit but
R misses is:
P ( E 1 ∩ E 2 ∩ E 3 ) = P ( E 1 ) ⋅ P ( E 2 ) ⋅ ( 1 − P ( E 3 ) ) = ‌ ⋅ ‌ ⋅ ‌ Now, summing these probabilities gives the required probability that the target is hit by
P or
Q , but not by
R :
P ( ‌ hit by ‌ P ‌ or ‌ Q ‌ but not ‌ R ) ‌ = P ( E 1 ∩ E 2 ∩ E 3 ) + P ( E 1 ∩ E 2 ∩ E 3 ) + P ( E 1 ∩ E 2 ∩ E 3 ) ‌ = ‌ ⋅ ‌ ⋅ ‌ + ‌ ⋅ ‌ ⋅ ‌ + ‌ ⋅ ‌ ⋅ ‌ ‌ = ‌ + ‌ + ‌ ‌ = ‌ Thus, the probability that the target is hit by
P or
Q but not by
R is
‌ .
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