Probability

Total outcomes ={1,2,3,4,5,6}=6
Prime number ={2,3,5}=3
So, P(A)=3∕6=1∕2
and even numbers ={2,4,6}=3
∴P(B)=3∕6=1∕2
Thus, P(B)=1−P(B)=1−1∕2=1∕2
Total sample for 2 throws =6×6=36
Then, P(A∕B)=‌

P(A∩B)

P(B)

First throw is prime ={2,3,5}
Second throw is not even ={1,3,5}
Pairs where first is in {2,3,5} and second is in {1,3,5}=3×3=9 outcomes
So, P(A∩B)=9∕36=1∕4
Therefore, P(A∕B)=‌

(1∕4)

(1∕2)

=1∕2