If {\A}=\left[\begin{array}{ccc}1 & 2 & 3 \ 1 & 3 & 5 \ 2 & 1 & 6]\end{array} and |{\adj}({\adj} {\A})|({\adj} {\A})^{-1}= {\kA}, then {\k}= [AP EAPCET 22 May 2025 S2]

Matrices and Determinants

Section: Mathematics

Question : 13 of 48

Marks: +1, -0

If A=[

] and |adj(adj‌A)|(adj‌A)−1=kA, then k=

[AP EAPCET 22 May 2025 S2]

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