Limits Continuity and Differentiability

Section: Mathematics

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Question : 28 of 61

Marks: +1, -0

lim

x⟶0

‌

(√2)−√1+cos‌x

√15+cos‌2‌x−4

=

[AP EAPCET 21 May 2025 S1]

−‌
1
√2
‌
1
√2
√2
−√2

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