\lim_{n \rightarrow \infty} [\frac{n+1}{n^2+1^2}+\frac{n+2}{n^2+2^2}+\frac{n+3}{n^2+3^2}+. . .+\frac{n+2 n}{n^2+4 n^2}] = [AP EAPCET 21 May 2025 S1]

Correct Answer is : Tan−12+12log5

{\Tan}^{-1} 2+\frac{1}{2} \log 3

\frac{\pi}{4}+\frac{1}{2} \log 3

{\Tan}^{-1} 2+\frac{1}{2} \log 5

\frac{\pi}{4}+\frac{1}{2} \log 5

Limits Continuity and Differentiability

Section: Mathematics

Question : 24 of 61

Marks: +1, -0

lim

n⟶∞

[‌

n+1

n2+12

+‌

n+2

n2+22

+‌

n+3

n2+32

+...+‌

n+2n

n2+4n2

[AP EAPCET 21 May 2025 S1]

Go to Question:

Prev Question

Next Question