Limits Continuity and Differentiability

Section: Mathematics

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Question : 2 of 61

Marks: +1, -0

lim

x⟶0

‌

x‌tan‌2‌x−2x‌tan‌x

(1−cos‌2‌x)2

=

[AP EAPCET 24 May 2025 S1]

‌−‌
1
2
‌‌
1
2
‌‌
1
4
‌1

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