Limits Continuity and Differentiability

Section: Mathematics

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Question : 19 of 61

Marks: +1, -0

lim

x⟶−∞

‌

5x3−x2sin‌5x

x‌cos‌4‌x+7|x|3−4|x|+3

=

[AP EAPCET 21 May 2025 S2]

‌
5
4
−‌
5
4
−‌
5
7
‌
5
7

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