Limits Continuity and Differentiability

Section: Mathematics

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Question : 14 of 61

Marks: +1, -0

lim

y⟶0

‌

√1+√1+y4−√2

y4

=

[AP EAPCET 22 May 2025 S1]

‌
1
4√2
‌
1
2√2(1+√2)
‌
1
2√2
‌
1
4√2(1+√2)

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