\int(\sqrt{\tan x}+\sqrt{\cot x}) \dx= [AP EAPCET 24 May 2025 S1]

Correct Answer is : √2Tan−1(tanx−1√2tanx)+c

2 {\Tan}^{-1} ( {\tan x-1}/{\sqrt{\tan x}}) +c

{\Tan}^{-1} ( {\tan x-2}/{2 \sqrt{\tan x}}) +c

\sqrt{2} {\Tan}^{-1} ( {\tan x-1}/{\sqrt{2 \tan x}}) +c

\sqrt{2} {\Tan}^{-1} ( {\tan x+1}/{\sqrt{2} \tan x}) +c

Indefinite Integration

Section: Mathematics

Question : 4 of 89

Marks: +1, -0

∫(√tan‌x+√cot‌x)‌dx=

[AP EAPCET 24 May 2025 S1]

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