\int \frac{13 \cos 2 x-9 \sin 2 x}{3 \cos 2 x-4 \sin 2 x} \dx= [AP EAPCET 22 May 2025 S2]

Correct Answer is : 3x−12log|3cos2x−4sin2x|+c

3 x-\frac{1}{2} \log |3 \cos 2 x-4 \sin 2 x|+c

\frac{x}{2}-3 \log |3 \cos 2 x-4 \sin 2 x|+c

3 x+\frac{1}{2} \log |3 \cos 2 x-4 \sin 2 x|+c

x+\frac{3}{2} \log |3 \cos 2 x-4 \sin 2 x|+c

Indefinite Integration

Section: Mathematics

Question : 10 of 89

Marks: +1, -0

∫‌

13‌cos‌2‌x−9sin‌2x

3‌cos‌2‌x−4sin‌2x

‌dx=

[AP EAPCET 22 May 2025 S2]

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