If y=\sqrt{\cosh x+{\sqrt{\cosh x}}, then \frac{d y}{d x}= [AP EAPCET 23 May 2025 S2]

Correct Answer is : sinhx(1+2√coshx)4y√coshx

\frac{ \sinh x (2 y^2+2 \cosh x+1) }{4 y (y^2+\cosh x) }

\frac{ \sinh x (2 y^2-2 \cosh x-1) }{4 y (y^2-\cosh x) }

{ \sinh x(1-2 \sqrt{\cosh x})}/{4 y \sqrt{\cosh x}}

{ \sinh x(1+2 \sqrt{\cosh x})}/{4 y \sqrt{\cosh x}}

Differentiation

Section: Mathematics

Question : 5 of 34

Marks: +1, -0

If y=√cosh‌x+√cosh‌x, then ‌

[AP EAPCET 23 May 2025 S2]

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