If y=\tan (\log x), then \frac{d^2 y}{d x^2}= [AP EAPCET 20 May 2024 Shift 1]

Correct Answer is : sec2(logx)[2tan(logx)−1]x2

\frac{-\sec ^2(\log x)[1+2 \tan x]}{x^2}

\frac{\sec ^2(\log x)[1+\tan (\log x)]}{x^2}

\frac{\sec (\log x)[2 \tan (\log x)-1]}{x^2}

\frac{\sec ^2(\log x)[2 \tan (\log x)-1]}{x^2}

Differentiation

Section: Mathematics

Question : 29 of 34

Marks: +1, -0

If y=tan(log‌x), then ‌

d2y

dx2

[AP EAPCET 20 May 2024 Shift 1]

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