The area of the region lying between the curves y=\sqrt{4-x^2}, y^2=3 x and the Y-axis is [AP EAPCET 22 May 2025 S1]

Correct Answer is : π3−12√3

\frac{\pi}{3}- {1}/{2 \sqrt{3}}

\frac{\pi}{6}+ {1}/{2 \sqrt{3}}

\frac{\pi}{3}+ {1}/{2 \sqrt{3}}

\frac{\pi}{6}- {1}/{2 \sqrt{3}}

Area under the Curves

Section: Mathematics

Question : 4 of 12

Marks: +1, -0

The area of the region lying between the curves y=√4−x2,y2=3x and the Y-axis is

[AP EAPCET 22 May 2025 S1]

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