If the lines x+y-2=0,3 x-4 y+1=0 and 5 x+k y-7=0 are concurrent at (\alpha, \beta), then equation of the line concurrent with the given lines and perpendicular to {\kx}+ {\y}- {\k}=0 is [AP EAPCET 22 May 2025 S2]

Correct Answer is : x−2y=−1

Straight Lines and Pair of Straight Lines

Section: Mathematics

Question : 26 of 81

Marks: +1, -0

If the lines x+y−2=0,3x−4y+1=0 and 5x+ky−7=0 are concurrent at (α,β), then equation of the line concurrent with the given lines and perpendicular to kx+y−k=0 is

[AP EAPCET 22 May 2025 S2]

x−3y=−2
x+4y=5
x+6y=7
x−2y=−1

Validate

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