What is {\E}_{\text{cell }} (in V) of the following cell at 298 K ? ( {\E}_{ {\Zn}^{2+} \/ {\Zn}}^{⊖}=-0.76 {\V} ; {\E}_{ {\Ni}^{2+} \/ {\Ni}}^{⊖}=-0.25 {\V} ; {2.303 {\RT}}/{ {\F}}=0.06 {\V}) {\Zn}( { s}){| {\Zn}^{2+}(0.01 {\M}) \|\| {\Ni}^{2+}(0.1 {\M}) |} {\Ni}( { s}) [AP EAPCET 21 May 2025 S1]

Electrochemistry

Section: Chemistry

Question : 9 of 20

Marks: +1, -0

What is E‌cell ‌ (in V) of the following cell at 298 K ?
‌(EZn2+∕Zn⊖=−0.76V;ENi2+∕Ni⊖=−0.25V;‌

2.303‌RT

=0.06V)
‌Zn( s)‌|Zn2+(0.01M)‌||Ni2+(0.1M)|‌Ni( s)

[AP EAPCET 21 May 2025 S1]

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