Chemical Equilibrium

Given reaction:
A2O4(g)⇌2AO2(g)
At 298 K , the equilibrium constant in concentration units isKc=xmolL−1.
We need to find the approximate value ofKP.
Relation between KP andKC
For a gaseous reaction:
KP=KC(RT)∆n
where
∆n=‌ (moles of gaseous products) ‌−‌ (moles of gaseous reactants) ‌
Step 1: Determine∆n
Moles of gaseous products=2
Moles of gaseous reactants=1
⇒∆n=2−1=+1

Step 2: Substitute into the relation
KP=KC(RT)1=KC(RT)
Step 3: Plug in the given values
AtT=298K,
R=0.082L‌atm‌mol−1K−1
RT=0.082×298=24.4L‌atm‌mol−1
Step 4: Therefore,
‌KP=KC×24.4
‌KP=24.4x
Final Answer: Option A -24.4x