The de Broglie wavelength of an electron with kinetic energy of 2.5 {\eV} is (in {\m} ) (1 {\eV}=1.6 \times 10^{-19} {\J}, {\m}_{ {\e}}=9 \times 10^{-31} {\kg}) [AP EAPCET 22 May 2024 Shift 2]

Correct Answer is : h×1025√72

{ {\h} \times 10^{-25}}/{\sqrt{72}}

{ {\h} \times 10^{25}}/{\sqrt{72}}

{\sqrt{72}}/{ {\h} \times 10^{-25}}

{\sqrt{72}}/{ {\h} \times 10^{25}}

Atomic Structure

Section: Chemistry

Question : 18 of 32

Marks: +1, -0

The de Broglie wavelength of an electron with kinetic energy of 2.5‌eV is (in m )
(1‌eV=1.6×10−19J,me=9×10−31‌kg)

[AP EAPCET 22 May 2024 Shift 2]

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