In a region of free space, the electric field at an instant of time is \overrightarrow{E}=(80 \hat{i}+32 \stackrel{⋀}{j}- 64\stackrel{⋀}{k}) V \cdot m^{-1} and the magnetic field is \overrightarrow{B}=(0.2 \hat{i}+0.08 \hat{j}+0.29 \hat{k}) T. The poynting vector is ______. Given magnetic permeability of free space is 4 \pi \times 10^{-7} {H} \cdot {m}^{-1}.

Correct Answer is : (11.46⋀i−28.65⋀j)×106W⋅m−2

(14.4 \stackrel{⋀}{i}-36 \stackrel{⋀}{j}) \times 10^{6} W \cdot m^{-2}

(14.4 \stackrel{⋀}{i}-26 \stackrel{⋀}{j}) \times 10^{6} W \cdot m^{-2}

(11.46 \stackrel{⋀}{i}-28.65 \stackrel{⋀}{j}) \times 10^{6} W \cdot m^{-2}

(11.46 \stackrel{⋀}{j}-15.65 \stackrel{⋀}{k}) \times 10^{6} W \cdot m^{-2}

AP EAPCET 7 Sep 2021 Shift 1 Paper

Question : 116 of 160

Marks: +1, -0

In a region of free space, the electric field at an instant of time is

→

=(80

∧

+32

⋀

− 64

⋀

)‌V⋅m−1 and the magnetic field is

→

=(0.2

∧

+0.08

∧

+0.29

∧

)T. The poynting vector is ______. Given magnetic permeability of free space is 4π×10−7H⋅m−1.

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