If {\y}= (\log _{ {\x}} \sin {\x}) ^{ {\x}}, then { {\dy}}/{ {\dx}}= [AP EAPCET 26 May 2025 S1]

Correct Answer is : y[xcotxlogsinx+log(logsinx)−1logx−log(logx)]

y [\frac{x \sin x}{\log \cos x}+\log (\log \sin x)+\frac{1}{\log x}-\log (\log x)]

y [\frac{x \cos x}{\log \sin x}-\log (\log \sin x)+\frac{1}{\log x}+\log (\log x)]

y [\frac{x \cot x}{\log \sin x}+\log (\log \sin x)-\frac{1}{\log x}-\log (\log x)]

y [\frac{x \cot x}{\log \sin x}-\log (\log \sin x)+\frac{1}{\log x}-\log x]

AP EAPCET 26 May 2025 Shift 1 Paper

Section: Mathematics

Question : 64 of 160

Marks: +1, -0

If y=(logxsin‌x)x, then ‌

[AP EAPCET 26 May 2025 S1]

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