The vector equation of a plane passing through the line of intersection of the planes \overline{ {\r}} \cdot(\overline{ {\i}}-2 \overline{ {\k}})=3, \overline{ {\r}} \cdot(2 \overline{ {\j}}+\overline{ {\k}})=5 and the point \overline{ {\i}}+2 \overline{ {\j}}+3 \overline{ {\k}} is [AP EAPCET 26 May 2025 S1]

Correct Answer is : r⋅(i+8j+2k)=23

\overline{ {\r}} \cdot(\overline{ {\i}}+4 \overline{ {\j}})=13

\overline{ {\r}} \cdot(\overline{ {\i}}+6 \overline{ {\j}}+\overline{ {\k}})=18

\overline{ {\r}} \cdot(\overline{ {\i}}+2 \overline{ {\j}}-\overline{ {\k}})=8

\overline{ {\r}} \cdot(\overline{ {\i}}+8 \overline{ {\j}}+2 \overline{ {\k}})=23

AP EAPCET 26 May 2025 Shift 1 Paper

Section: Mathematics

Question : 31 of 160

Marks: +1, -0

The vector equation of a plane passing through the line of intersection of the planes r⋅(i−2k)=3,r⋅(2j+k)=5 and the point i+2j+3k is

[AP EAPCET 26 May 2025 S1]

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