AP EAPCET 25-Aug-2021 Shift 2 Paper

Given The system of equations x+2y=3,
3x+6y=a−2 has no solution.
Since, we know that simultaneous linear equations
a1x+b1y=c1 and a2x+b2y=c2 has no solution,
if

a1

a2

=

b1

b2

≠

c1

c2

Hence, from the given equations,
⇒

1

3

=

1

3

≠

3

a−2

To satisfy above condition, a−2≠9
⇒ a≠11