AP EAPCET 25-Aug-2021 Shift 2 Paper

Given, equation of circle is
5x2+5y2=1 ⇒ x2+y2=(

1

√5

)2
Given, line is 3x+4y=1
⇒ Slope (m)=

−3

4

Since, we know that tangents to the circle x2+y2=a2 in the slope form is given by
y=mx±a√1+m2 ...(i)
Since, required line is parallel to given line, hence it will have same slope and radius =

1

√5

From Eq. (i), we get
y=

−3

4

x±

1

√5

√1+(

−3

4

)2 =

−3

4

x±

1

√5

√

25

16

y=

−3x

4

±

1

√5

×

5

4

⇒4y=−3x±√5
⇒ 3x+4y=±√5