AP EAPCET 25-Aug-2021 Shift 2 Paper

Relation between activation energy (Ea) and rate constant (k).
⇒ k=Ae−

Ea

RT

Here, A= frequency factor or pre-exponential factor.
T= temperature (in K)
R= gas constant
e= mathematical quantity
Now, at 273K,Ea=0
k1=Ae−

0

R×273

k1=A.1
k1=A ...(i)
Similarly at, 383K,
k2=Ae−

Ea

383

...(ii)
Ratio of Eqs. (i) and (ii) is
k2=k1e−

Ea

383

If, ΔEa=0
k2=k1
Hence, ratio of rate constant at 383K is 1.