AP EAPCET 25-Aug-2021 Shift 2 Paper

For the reaction,

1

2

C(g)⇌

1

2

A(g)+

1

2

B(g)
Given, Kp=0.25atm−2
We know that, KC=

[Product]b

[Reactant]a

, where a and b are stiochiometric coefficients.
Also, Kp=KC(RT)Δng
where, Δng=b−a
For above reaction, KC1=

[A]0.5[B]0.5

[C]0.5

Δng=1−0.5=0.5
So, Kp1=KC1(RT)0.5 ...(i)
Similarly for reaction,
A(g)+B(g)⇌C(g), at same temperature
Kc2=

[C]

[A][B]

Δng=1−2=−1
Kp2=KC2(RT)−1 ...(i)
Now, divide Kp1 and Kp2, we get

Kp1

Kp2

=

KC1[RT]0.5

KC2[RT]−1

⇒ Kp2=16‌atm

So, Kp for the reaction
A(g)+B(g)⇌C(g) is 16‌atm