A particle of mass 0.4 { kg} executes simple harmonic motion of amplitude 0.4 { m}. When it passes through the mean position, its kinetic energy is 256 \\times10^{-3} { J}. If the initial phase of the oscillation is \frac{\\pi}{4}, then the equation of its motion is _______

Correct Answer is : x=0.4sin((2√2)t+π4)

x=0.4 \sin ((0.4) t+\frac{\\pi}{4})

x=0.2 \sin (2 \\sqrt{2}+(\frac{\\pi}{4}) t)

x=0.8\sin ((2 \\sqrt{2})t+\frac{\\pi}{2} )

x=0.4\sin ((2 \\sqrt{2})t+\frac{\\pi}{4} )

AP EAPCET 25-Aug-2021 Shift 1 Paper

Section: Physics

Question : 94 of 160

Marks: +1, -0

A particle of mass 0.4 kg executes simple harmonic motion of amplitude 0.4 m. When it passes through the mean position, its kinetic energy is 256×10−3 J. If the initial phase of the oscillation is

, then the equation of its motion is _______

x=0.4‌sin((0.4)t+
π
4
)
x=0.2‌sin(2√2+(
π
4
)t)
x=0.8‌sin((2√2)t+
π
2
)
x=0.4‌sin((2√2)t+
π
4
)

Validate

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