AP EAPCET 25-Aug-2021 Shift 1 Paper

Let, M be the mass of the thin rod and L be the length of thin rod.
Moment of inertia of thin rod about its centre of
mass, Iсom=

1

12

ML2
By parallel axis theorem,
Moment of inertia about an axis = Moment of inertia about centre of mass + Mass times‌1 distance from axis )2
⇒I=Icom+M(d)2
=

1

12

ML2+M(

L

4

)2 (Given, d=

L

4

)
=(

4+3

48

)ML2=

7

48

ML2