AP EAPCET 25-Aug-2021 Shift 1 Paper

The velocity acquired by a mass m falling freely under the influence of gravity from the heigh h is
v=√2gh
Momentum of first body, p1=m1v1
⇒ =m1√2gh1
Momentum of second body p2=m2v2
⇒=m2√2gh2
The ratio of their linear momenta on touching the ground is

p1

p2

=

m1√2gh1

m2√2gh2

=

2

3

×√

9

16

=

2

3

×

3

4

=

1

2

or 1:2