AP EAPCET 25-Aug-2021 Shift 1 Paper

According to thermodynamics irreversibly expanded system work.
Wint=−pepp(V2−V1) ...(i)
Ideal gas expanded irreversibly =10 bar
V2=30L
V1=20L
Put all value in Eq. (i), we get
Wint=−10 bar (30−20)L
=−9.869‌atm×10L
= -9999.76 J
= -10kJ
Since, for expanded irreversibly, ΔH=0
∴ (ΔH=0 i.e. isoenthalpic process)
Q=−Wint
Q=−(−10‌kJ)
Q=10‌kJ
Hence, Qvalue of isoenthalpic process is 10‌kJ.