AP EAPCET 25-Aug-2021 Shift 1 Paper

Kinetic energy (KE)=

3‌nRT

2

Here, n= number of moles
T= temperature
R= rate constant
Now, kinetic energy of He = total KE of Ar
Now,

KE‌of‌He

KE‌of‌Ar

=

(mole‌of‌He)×(temp.of‌He)

(mole‌of‌Ar)×(temp.of‌Ar)

1=

0.30×T1

0.40×400

⇒ T1=

0.40×400

0.30

T1=533K
Hence, at temperature 533K, KE of He and Ar will be same.