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Question : 72 of 160
Marks:
+1,
-0
Solution:
‌‌ Let ‌I=∫‌‌dx‌=∫‌‌dx‌=∫‌+∫‌‌dxLet
u=x2−2x+5, then
du=(2x−2)‌dx=‌2(x−1)‌dx=‌‌‌∫‌+∫‌‌dx=‌‌(2u‌)+sin‌h−1‌+C‌[∵∫‌=sin‌h−1‌]Where,
C= constant
=√u+ sinh−1(‌)+C=√x2−2x+5+ sinh−1(‌)+C
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