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Question : 70 of 160
Marks:
+1,
-0
Solution:
‌‌ Let ‌I=∫‌‌dx‌‌ and ‌u=√x−2‌⇒u2=x−2‌ and ‌x=u2+2Differentiate
x w.r.t
u, we get
‌‌=2u⇒dx=2uduI‌=∫‌‌dx=∫‌du‌=∫‌du=∫‌du‌=∫‌du=∫(1−‌)du‌=u−4⋅‌⋅tan−1(‌)+Cwhere,
C= constant
‌=u−2tan−1(‌)+C‌=√x−2−2tan−1(‌)+C
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