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Question : 20 of 160
Marks:
+1,
-0
Solution:
Given, expression is
tan(‌)⋅tan(‌)+tan(‌)⋅tan(‌)+tan(‌)⋅tan(‌)Let
x=‌,y=‌ and
z=‌So, the expression becomes
tan(y)â‹…tan(z)+tan(z)â‹…tan(x)+tan(x)â‹…tan(y)Now,
x+y+z=‌+‌+‌=‌=πSince,
x+y+z=Ï€, we can use the identify
‌tan(x)⋅tan(y)+tan(y)⋅tan(z)+tan(z)⋅tan(x)=−7‌∴tan(‌)‌tan(‌)+tan(‌)⋅tan(‌)+tan(‌)‌tan(‌)=−7
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