AP EAPCET 24-Aug-2021 Shift 2 Paper

Given that, T be the time period of simple pendulum when lift is at rest. Then,
T=2π√

l

g

...(i)
When the lift is moving upwards with an acceleration a=3g, the new time period will be
T′=2π√

1

g+a

=2π√

l

4g

...(ii)
Dividing Eq. (ii) by Eq. (i), we get

T′

T

=

2π√ 1 g

2π√ 1 4g

=

2

1

⇒T′=

T

2