AP EAPCET 24-Aug-2021 Shift 2 Paper

Given that, mass of shell =m
Mass of Lst part, m1=

m

6

Then, mass of 2nd part, m2=m−

m

6

=

5m

6

Velocity of lst part, v1=0
Velocity of shell =v
Let velocity of 2nd part =v2
By using law of conservation of linear momentum, Initial linear momentum = final linear momentum.
mv=m1v1+m2v2
Substituting the values, we get
mv=

m

6

×0+

5m

6

×v2
⇒v2=

6

5

v
Hence, the velocity of 2nd part is

6

5

v in the same direction as that of shell.