AP EAPCET 24-Aug-2021 Shift 2 Paper

Section: Mathematics

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Question : 59 of 160

Marks: +1, -0

The equation of hyperbola whose eccentricity is

5

3

and distance between the foci is 10 units is:

16x2−9y2=16
16x2−9y2=9
16x2−9y2=−144
16x2−9y2=144

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