AP EAPCET 24-Aug-2021 Shift 2 Paper

Given that, number of loops, N=500
Side of square, a=10‌cm=0.1m
Rate of increase of magnetic field,

dB

dt

=1T∕s
Now, induced emf, ε=−N

dϕ

dt

=−N

d

dt

(BA)
=−NA‌

dB

dt

=−Na2

dB

dt

[∵ Area of square A=a2]
Substituting the values, we get
ε=−500×(0.1)2×1=−5V
Magnitude, |ε|=5V