AP EAPCET 24-Aug-2021 Shift 1 Paper

Given that, moment of inertia, I=10‌kg−m2
Initial angular velocity, ω0=50‌rad∕s
Final angular velocity, ω=0
Time taken to stop wheel, t=10s
We know that, work done by torque = change of rotational KE
W=Δ‌KE=Kf−Ki
W=

1

2

Iω2−12Iωa2
W=0−

1

2

×10×(50)2
= -12500 J
So, amount of work done to bring the flywheel to rest is 12500J.