AP EAPCET 24-Aug-2021 Shift 1 Paper

Given, radius of curvature, r=250m
Maximum velocity of train, v=90kmh−1
=

90×5

18

m∕s=25m∕s
Let θ be the angle of banking of railway track.
Then, by using an expression of maximum safe speed.
v2=rg‌tan‌θ
⇒tan‌θ=

v2

rg

By substituting the values, we get
tan‌θ=

(25)2

250×10

=

625

2500

=

1

4

∴ θ=tan−1(

1

4

)