AP EAPCET 24-Aug-2021 Shift 1 Paper

Given,
curve, y=x3
∵ Slope of tangent to the curve at any point (x1,y1) on the curve is =

dy

dx

|(x1,n1)
So,

dy

dx

=3x2
∴ Slope of tangent at (x1,y1) is mT=3x12
∵ Tangent is parallel to X-axis ⇒mT= Slope of X-axis
⇒mT=0
⇒3x12=0
⇒x1=0
⇒y1=0
∴ Point of contact is (0,0)