© examsiri.com
Question : 7 of 160
Marks:
+1,
-0
Solution:
Given,
2x+6y=−11 6x+20y−6z=−3 6y−18z=−1 Using Cramer's rule,
D=|| =2(20×(−18)−6×(−6)−6(6×(−18)−(−6)×0)
=2(−360+36)−6(−108) =2(−360+36)−6(−108) =2(−324)+648 =−648+648=0 D1=|| −11 | 6 | 0 |
| −3 | 20 | −6 |
| −1 | 6 | −18 |
| =−11(−324)−6(54−6) =−3564−6(48) =−3564−288=−3852≠0 D2=|| 2 | −11 | 0 |
| 6 | −3 | −6 |
| 0 | −1 | −18 |
| =2(54−6)+11(−108) =2(48)+(−1188)=96−1188=−1092≠0 D3=|| =2(−20+18)−6(−6)−11(36) =−4+36−396=−364≠0 ∵D=0,D1≠D2≠D3≠0 ⇒ Inconsistent solution.
© examsiri.com
Go to Question: