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Question : 64 of 160
Marks:
+1,
-0
Solution:
| xSin−1() |
| Cos−1()Tan−1() |
∵ We know that
x→0+ 2tan−1x=sin−1=cos−1() 3tan−1x=tan−1() ∴ Limit becomes
| x.(2tan−1x) |
| (2tan−1x)(3tan−1x) |
}
⇒ Using L Hospital rule
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